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From: | Matt Ettus |
Subject: | Re: [Discuss-gnuradio] ADC Specs |
Date: | Mon, 15 Dec 2008 15:47:13 -0800 |
User-agent: | Thunderbird 2.0.0.18 (X11/20081119) |
I'm afraid I dont understand. Are you saying I should be calculating:P = (0.707V)^2/50 OhmsP = 10mWor P = (0.707V)^2/200 OhmsP = 2.5mW
The first one, 10mW, is what a signal source would be providing to the BasicRX or LFRX input. So if you set your signal generator to 10 dBm, you should see a signal at roughly full-scale.
The second one is the power that would be consumed at the input of the ADC, but that is a completely meaningless number.
Matt
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