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Re: [Discuss-gnuradio] A simple analogue question.
From: |
Brian Padalino |
Subject: |
Re: [Discuss-gnuradio] A simple analogue question. |
Date: |
Sun, 11 Apr 2010 11:07:04 -0400 |
On Sun, Apr 11, 2010 at 10:12 AM, Sebastiaan Heunis <address@hidden> wrote:
> Hi everyone.
>
> I was wondering if someone could please answer the following question?
>
> If I have two signals entering a receiver, both with a power of 0 dBm,
> what would be the total input power seen by the receiver? Is it 3 dBm
> or 6 dBm?
Bringing it back to power instead of ratios helps clear this up. Both
transmitters are emitting 1mW, for a total input power of 2mW.
Calculating dBm on that yields:
10*log10(2mW/1mW) = 3dBm
Hope this helps!
> Thanks.
>
> Sebastiaan
Brian