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From: | Josh Blum |
Subject: | Re: [Discuss-gnuradio] Question about UHD output data type. |
Date: | Tue, 19 Oct 2010 09:25:20 -0700 |
User-agent: | Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1.12) Gecko/20100915 Thunderbird/3.0.8 |
I met a strange problem about UHD output data. I write the sampler program according to rx_timed_samples.cpp and use int 16 bits as io type as in command: size_t num_rx_samps = dev->recv( buff, sizeof(buff), md, uhd::io_type_t::COMPLEX_INT16, uhd::device::RECV_MODE_ONE_PACKET ); Then I checked the output data and found that samples seems to be the int 8 bit data since the minimum step is 0.0078125, which is equal to 2 power of -7. What could be the reason for this?
The range of an int16 is +/-2^15, the minimum step is 1 because its an integer. Did you by any change change the io type to int16, but interpret the buffer as a complex float?
-josh
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