Re: [Discuss-gnuradio] GUI to display transmitted signal

[Tom Rondeau]

On Wed, Feb 20, 2013 at 1:39 PM, Brooke Hayden <address@hidden> wrote:

I am transmitting a signal from my USRP N210, but I would like to also see that signal on screen in a gui. I'm currently getting an error that I don't understand. I have a simple class, tx_test(gr.heir_block2), that simply transmits a sine wave.

The second class, tx_sink(stdgui2.std_to_block), has the following things:
def __init__(self, frame, panel, vbox, argv):
        stdgui2.std_top_block.__init__ (self, frame, panel, vbox, argv)
       
        parser = OptionParser(option_class=eng_option)

        parser.add_option .....adds some options....

        (options, args) = parser.parse_args ()
        self.u = uhd.usrp_sink(device_addr=options.args,
                                          stream_args=uhd.stream_args('fc32'))
It goes on to set sample rates and such. Lastly I have:
         sig0 = tx_test(options.samp_rate)
         self.connect(sig0, self.u)
        
         gui = fftsink2.fft_sink_c(panel, title="Tx FFT Plot",
                                             fft_size=1024, sample_rate=self.usrp_rate)
        self.connect (sig0, gui)
        vbox.Add (gui.win, 1, wx.EXPAND)

def main ():
    app = stdgui2.stdapp(tx_sink, "Transmitted Signal", nstatus=1)
    app.MainLoop ()

if __name__ == '__main__':
    main ()

I get the following error:
File "tx_test_gui.py", line 47, in tx_sink
    self.u = uhd.usrp_sink(device_addr=options.args, stream_args=uhd.stream_args('fc32'))
NameError: name 'self' is not defined

My first guess to this is incorrect whitespace. Make sure your "def __init__" function is properly set under the class name and there's no odd spacing anywhere else (or that you have both tabs and spaces that are confusing the parser).

Tom