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Subject: |
30.0.50; tree-sitter: identical nodes are not `equal' |
Date: |
Sun, 08 Jan 2023 14:55:16 +0000 |
In order to check for node equality, one must use `treesit-node-eq'.
But I see little reason why two identical nodes in in the same tree aren't
`equal'?
In GNU Emacs 30.0.50 (build 6, x86_64-pc-linux-gnu, GTK+ Version
3.24.20, cairo version 1.16.0) of 2023-01-02 built on mickey-work
Repository revision: c209802f7b3721a1b95113290934a23fee88f678
Repository branch: master
Windowing system distributor 'The X.Org Foundation', version 11.0.12013000
System Description: Ubuntu 20.04.3 LTS
Configured using:
'configure --with-native-compilation --with-json --with-mailutils
--without-compress-install --with-imagemagick CC=gcc-10'
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--- Begin Message ---
Subject: |
Re: bug#60659: 30.0.50; tree-sitter: identical nodes are not `equal' |
Date: |
Thu, 12 Jan 2023 17:08:14 -0800 |
Eli Zaretskii <eliz@gnu.org> writes:
>> From: Yuan Fu <casouri@gmail.com>
>> Date: Tue, 10 Jan 2023 18:57:02 -0800
>> Cc: larsi@gnus.org,
>> monnier@iro.umontreal.ca,
>> 60659@debbugs.gnu.org
>>
>> But still, using a C functions is more correct. How about this?
>
> Yes, this is what I had in mind. Thanks.
Cool. I applied it.
Yuan
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