Re: What happens when I evaluate the call the second time?

[Mathias Dahl]

> First C-x C-e after the function, then twice after calling it. The
> output is:
> average
> 2
> 2 (#o2, #x2, ?\C-b)
>
> Now what's the (#o2, #x2, ?\C-b) stuff?

Different ways to express 2 I think. What I find strange however, is
that it is only displayed at the second invocation of C-x C-e. If you
for example move point left and right and evaluate again, you first
get 2, then the above.

> PS. I notice that the output is 2 and not 2.5, I guess the output gets
> truncated to an integer (the decimal part is discarded).

Yes. Try with (average 2.0 3) and you will get 2.5.