Re: Don't move to eol in end-of-defun?

[Alan Mackenzie]

Hello, Filipp.

On Mon, Aug 01, 2022 at 01:31:28 +0300, Filipp Gunbin wrote:
> On 31/07/2022 01:40 +0200, Daniel Martín wrote:

> > Filipp Gunbin <fgunbin@fastmail.fm> writes:

> >> In Java, it's a common style to have hanging parentheses:

> >> class C <1>{<2>
> >>   void foo() {
> >>   }<3>
> >> }<4>

> >> If we're at position <1> and press C-M-e, then it's logical to move to
> >> <4>, and that's what I implement in javaimp package, by defining my own
> >> beginning-of-defun-function / end-of-defun-function.

Be aware that end-of-defun-function is broken.  Before calling e-o-d-f,
end-of-defun first moves point somewhere else and then calls it.  That
somewhere else could easily be in a different function.  Say if you have

class C <1>{ <2>void foo () {
             }<3>
}<4>

and start at <1>, that somewhere else is likely to be <2> from where
your e-o-d-f will probably go to <3>.

> > If I yank your sample program in a buffer in Java mode, with point at
> > <1>, C-M-e goes to <4>, as expected.  So I don´t know why you need to
> > implement your own end-of-defun-function in your package.

> I'd like to not rely on java-mode (part of cc-mode).

Be further aware that in languages like Java, you can't do a fully
accurate job without scanning braces back to BOB.  CC Mode has its own
c-end-of-defun function, which uses a cache of brace blocks, for the
reasons in this post (amongst others).  You're welcome to take stuff
from it, if that might help.

> Thanks.

-- 
Alan Mackenzie (Nuremberg, Germany).