[Fab-user] bash variable substitution

[Vincent Fretin]

Hi,

bash variable substitution worked in Fabric 0.1. With Fabric 0.9a3, it
doen't work anymore

def echo():
    run("VAR='myvar'; echo $VAR")

returns a blank line instead of myvar:
[host] run: VAR='myvar'; echo $VAR
Password for address@hidden:

Done.

Using bash variable was the only way I could find Fabric 0.1 to do the
things I wanted.
In fabric 0.9a3, I think I can find another way, but I have to adapt
all my scripts.

Regards
-- 
Vincent Fretin