[lsd0003] branch master updated: Added some improvments strata descriptioN

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elias-summermatter pushed a commit to branch master
in repository lsd0003.

The following commit(s) were added to refs/heads/master by this push:
     new 5b68667  Added some improvments strata descriptioN
5b68667 is described below

commit 5b68667dc8e9e04b0aa01e46879920414afb7213
Author: Elias Summermatter <elias.summermatter@seccom.ch>
AuthorDate: Mon Dec 21 12:13:36 2020 +0100

    Added some improvments strata descriptioN
---
 draft-summermatter-set-union.xml | 13 ++++++++-----
 1 file changed, 8 insertions(+), 5 deletions(-)

diff --git a/draft-summermatter-set-union.xml b/draft-summermatter-set-union.xml
index 2bb3504..d505fd3 100644
--- a/draft-summermatter-set-union.xml
+++ b/draft-summermatter-set-union.xml
@@ -371,11 +371,14 @@
                 <t>
                     The trick is to decode the SE with the biggest stratum 
first and calculate the difference of
                     the set if the SE decodes successfully decode the next 
smaller strata estimator repeat
-                    this until the decoding of the SE fails or Stratum 0 is 
reached. Then its possible to estimate  ### Wie berechne ich den strata 
estimator Decodieren wie ist die formal um die
-                    how big the difference between two sets is by calculating 
the count of                          ### 2^n*k k=elemente (Durchnitt duch alle 
die estimatoren) Systamatischer pyas
-                                                                               
                                     ### Wie ist die formel sein?
-                    decoded elements divided by the stratum factor. If no of 
the SE decoded choose a smaller stratum or
-                    try a other hash function.
+                    this until the decoding of the SE fails or Stratum 0 is 
reached. Then its possible to estimate
+                    how big the difference between two sets is by adding the 
number of extracted hashes up (C) and scale it
+                    by the expected number of elements (E) in the remaining 
unencoded IBF's (C*E=[estimated count of objects]).
+                    If no of the SE decoded choose a smaller stratum or try a 
other hash function.
+
+                    ### Wie berechne ich den strata estimator Decodieren wie 
ist die formal um die
+                    ### 2^n*k k=elemente (Durchnitt duch alle die estimatoren) 
Systamatischer pyas
+                    ### Wie ist die formel sein?
                 </t>
             </section>
         </section>

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