Re: string escaping in bash

[Alex fxmbsw7 Ratchev]

thank you, fixing it.. trying some backslash only method now [or wish..]

thank you tho !

On Fri, Mar 12, 2021 at 8:45 PM Lawrence Velázquez <vq@larryv.me> wrote:

> > On Mar 12, 2021, at 2:28 PM, Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
> wrote:
> >
> > i dunno ..thats what its supposed to give, \\ give a \
> > so the dude wanted in his initial mail[s]
>
> My fault, this is what I meant to send:
>
> bash-5.1$ str=$'contains ^A: \1'
> bash-5.1$ printf '%s' "$str" | od -ta -tx1
> 0000000    c   o   n   t   a   i   n   s  sp   ^   A   :  sp soh
>            63  6f  6e  74  61  69  6e  73  20  5e  41  3a  20  01
> 0000016
> bash-5.1$ str=${str//\\\\/$'\1'} str=${str//\\n/$'\n'}
> str=${str//\\t/$'\t'}
> bash-5.1$ str=${str//$'\1'/\\}
> bash-5.1$ printf '%s' "$str" | od -ta -tx1
> 0000000    c   o   n   t   a   i   n   s  sp   ^   A   :  sp   \
>            63  6f  6e  74  61  69  6e  73  20  5e  41  3a  20  5c
> 0000016
>
> As you can see, the SOH character (^A, \001, etc.) in the original
> string has been mangled.
>
> --
> vq