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Re: string escaping in bash
From: |
Peng Yu |
Subject: |
Re: string escaping in bash |
Date: |
Fri, 12 Mar 2021 15:14:44 -0600 |
Hi Eli,
> Instead of doing successive, full passes as you replace each token, your
> program e.g. /usr/bin/pengus-whitespace-only-printf might want to read
> in the string character by character, detect whichever replacement token
> might be there, replace it, and move on. This would retain progress
> state, and therefore avoid processing the same tokens twice.
That is exactly a solution that I sent in a follow-up email. I clearly
defined what I meant by string escaping in the first email. Knowing
there is not a simpler but robust solution than my implementation is
totally fine. I want to confirm the answer is indeed "No".
--
Regards,
Peng
- Re: string escaping in bash, (continued)
- Re: string escaping in bash, Alex fxmbsw7 Ratchev, 2021/03/12
- Re: string escaping in bash, Alex fxmbsw7 Ratchev, 2021/03/12
- Re: string escaping in bash, Alex fxmbsw7 Ratchev, 2021/03/12
- Re: string escaping in bash, Lawrence Velázquez, 2021/03/12
- Re: string escaping in bash, Alex fxmbsw7 Ratchev, 2021/03/12
- Re: string escaping in bash, Alex fxmbsw7 Ratchev, 2021/03/12
- Re: string escaping in bash, Pier Paolo Grassi, 2021/03/12
- Re: string escaping in bash, Alex fxmbsw7 Ratchev, 2021/03/12
- Re: string escaping in bash, Pier Paolo Grassi, 2021/03/12
Re: string escaping in bash, Eli Schwartz, 2021/03/12
- Re: string escaping in bash,
Peng Yu <=
Re: string escaping in bash, Koichi Murase, 2021/03/13