Re: regex capturing the left-hand side of =

[Peng Yu]

I don't parse bash code to see the left-hand is valid or not without
eval the bash code.

On 7/10/21, Eli Schwartz <eschwartz@archlinux.org> wrote:
> On 7/10/21 8:07 AM, Peng Yu wrote:
>> Hi,
>>
>> I want to capture the left-hand side of =.
>
>
> I don't understand this? You already know the left hand side because you
> know what you wrote, the assignment operator doesn't let you do expansions.
>
>
>> Since bash variables can be at the left-hand side of =, it is easy to
>> be captured this case by a regex like ^[A-Za-z_][A-Za-z0-9_]$.
>
>
> I don't understand this? Bash variables can be on the right hand side,
> not the left hand side. Valid names for a bash variable can be on the
> left hand side... names, not actually variables.
>
> You can't do
>
> $var=foo
>
>
>> But it is not easy to capture assignments to elements in arrays or
>> associative arrays due to the complexity in the suffixes in between
>> [].
>
>
> What is so complex about it? You have a bash parser at /bin/bash which
> can evaluate that complexity for you (at the time you run the script, no
> less).
>
>
>> Is there a regex that can capture and only capture all bash code
>> snippets for the left-hand side of the assignment operator =?
>
>
> So now there is supposed to be "bash code snippets" on the LHS of an
> assignment operator??? How???
>
> What are you trying to do? (I know, I know, anyone asking "what are you
> trying to do" and expecting Peng Yu to answer is the most foolish fool
> in the world. But I'm going to ask anyway, in order to establish
> precedent in the discussion thread that "this question needs to be
> answered and naive readers shouldn't get the erroneous impression this
> thread is a good example to follow".)
>
> Why are you even trying to "capture" anything here? Clearly this can't
> be done inside of the script itself. Are you building a bash parser in
> another language?
>
>
> --
> Eli Schwartz
> Arch Linux Bug Wrangler and Trusted User
>
>


-- 
Regards,
Peng