Re: Problem printing 24 hour times OR a stupid mistake

[Chris Elvidge]

On 09/01/2022 14:13, Dennis Williamson wrote:
> On Sun, Jan 9, 2022, 6:57 AM Chris Elvidge <celvidge001@gmail.com> wrote:
>
> > On 08/01/2022 15:15, Chris Elvidge wrote:
> > > Given tim12="7:00 am" and tim24=$(date -d"$tim12" +"%H%M")
> > >
> > > printf '%04d' "$tim24" prints 0488; '%04o' will output 0700
> > >
> > > But if tim12="7:00 pm" and tim24=$(date -d"$tim12" +"%H%M")
> > > '%04d' gives the correct output 1900 but '%04o' gives 3554
> > >
> > > I have got round the problem with tim24=$(date -d"$tim12" +"%-H%M") i.e.
> > > stripping leading zeros, but is there any way to force printf to
> > > recognise 0700 as a decimal number?
> >
> > The stupid mistake is treating 0700 as a number - it is a string after
> > all, %H%M is a 4 character sequence.
> > printf '%s\n' "$(date -d"$tim12" +"%H%M")" works perfectly.
> >
> > --
> > Chris Elvidge
> > England
>
>
> You should be able to omit the printf and just do
>
> date -d"$tim12" +"%H%M"
>
> >

Agreed, but to get it to print time+separator+programme description, all 
on one line I need printf '%s|%s\n' "$tim24" "$progname" (or even echo 
"$tim24|$progname"). Anyway, printing as %s instead of %04d removed the 
problem.
Cheers.


--
Chris Elvidge
England