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Re: declare -f changes 'elif' to 'else if'

From: Chet Ramey
Subject: Re: declare -f changes 'elif' to 'else if'
Date: Mon, 21 Feb 2022 10:57:17 -0500
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:91.0) Gecko/20100101 Thunderbird/91.6.0

On 2/21/22 9:27 AM, sukolyn via wrote:

here's the picture :

$ myFunc() { if test foo; then : ; elif test bar; then : ; else : ; fi;}

$ declare -f myFunc

myFunc ()
     if test foo; then
         if test bar; then

`else' should be subordonate(?) to main `if' (i.e. `foo' command), not to inner if (`bar' command)

What does this mean? `elif' is just syntactic sugar for `else if'; they are
equivalent internally. There's no reason to have a special parse tree
representation for `elif', so when the internal parse tree gets converted
back to an external form, you get `else if'.

``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU

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