Re: declare -f changes 'elif' to 'else if'

[Chet Ramey]

On 2/21/22 9:27 AM, sukolyn via wrote:
> hi,
>
> here's the picture :
>
> $ myFunc() { if test foo; then : ; elif test bar; then : ; else : ; fi;}
>
> $ declare -f myFunc
>
> myFunc ()
> {
>      if test foo; then
>          :;
>      else
>          if test bar; then
>              :;
>          else
>              :;
>          fi;
>      fi
> }
>
> `else' should be subordonate(?) to main `if' (i.e. `foo' command), not to 
> inner if (`bar' command)

What does this mean? `elif' is just syntactic sugar for `else if'; they are
equivalent internally. There's no reason to have a special parse tree
representation for `elif', so when the internal parse tree gets converted
back to an external form, you get `else if'.

--
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/