Re: [Help-glpk] If-then expression: invalid use of reserved keyword if

[Nilo Cesar Teixeira]

In this example, suppose that I want to print '*' a single time if x[a] is 0 for everyone, and a if x[a] is 1.

(supposing that A is an elemental set, and a is symbolic, and x[a] = 1 for at most one a).

Ideas ? Simple formatting but I miss it.

Thank you.

2011/11/1 glpk xypron <address@hidden>

Hello Kasper,

in GMPL "if" is not a statement but an _expression_. The following
is a valid use of if:

set A := {1..4};
param x{A};
printf {a in A} ( if x[a] then "x[%s] = %d\n" else "" ), a, x[a];
data;
param x :=
 1 0
 2 2
 3 0
 4 1;
end;

Best regards

Xypron


-------- Original-Nachricht --------
> Datum: Tue, 1 Nov 2011 15:11:33 +0100
> Betreff: [Help-glpk] If-then _expression_: invalid use of reserved keyword if

> Hi guys
>
> I was trying to make a simple if-then statement as below, but failed with
> the error: "invalid use of reserved keyword if".
> I then tried searching the archive but the closest I got to an answer, was
> that it is not allowed to use if-then like this.
> Anyone know a workaround for that?
> I got a lot of 0-entries in 'x' and i simply just want to print the ones
> that is set to 1
>
> for {r in R} {
>  for {s in S} {
>   for {i in 1..fr[r]} {
>    if x[s,r,i] = 1 then printf "x[%s,%s,%i] = %i\n", s,r,i,x[s,r,i]
>   }
>  }
> }
>
> Best regards,
> Kasper

--
Follow me at http://twitter.com/#!/xypron

Empfehlen Sie GMX DSL Ihren Freunden und Bekannten und wir
belohnen Sie mit bis zu 50,- Euro! https://freundschaftswerbung.gmx.de

_______________________________________________
Help-glpk mailing list
address@hidden
https://lists.gnu.org/mailman/listinfo/help-glpk

--
Nilo Cesar Teixeira
address@hidden