RE: open file/buffer and insert date into it

[Bingham, Jay]

All things are possible to those that believe.

If what you want is to automatically date a file every time it is written,
take a look at the function time-stamp in the package time-stamp.el

If you want a function that can be used for inserting dates in log files
then you could use something like this:

(defvar tl_dts-format-string "%e %b %Y %H:%M:%S"
  "A string specifying the format of the date-time stamp.
Refer to the documentation for format-time-string for an explanation of the
meta characters available for use in this string.  Non-meta characters will
be inserted into the buffer without interpretation.")

;; Function: insert-dts
;;   Insert the date and time into the current buffer at the current
location.
;;
;; Psuedo code:
;;  insert the date and time into the current buffer at the current location
;;
(defun insert-dts ()
  "Insert the date and time into the current buffer at the current location.
See the documentation for tl_dts-format-string to change the format of the
date-time stamp."
  (interactive)
  (insert (format-time-string tl_dts-format-string (current-time))))

J_)
C_)ingham
.    COMPAQ Telecommunications
.    Austin, TX

 -----Original Message-----
From:   Kenneth E. Fisler [mailto:kefisler@sherwin.com] 
Sent:   Thursday, 28 June, 2001 10:43 a
To:     GNU Emacs Help
Subject:        open file/buffer and insert date into it





While we're talking about inserting a date, I would like to open a file
(actually a buffer) and insert some text and today's date into it, something
like:

(defun datefile (dfname)
  "Open file with date in it two times."
  (interactive
   (prgn
    (find-file dfname)
; buffer should have text in it something like:
; "Today is " (format-time-string "%Y-%m-%d" nil)
)))

Can this be done?  How?


tia,
kf



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