Re: Another replace regexp with list question

[Leandro Marcolino]

Oh, I see.... I didn't know about the "narrow" and "widen" commands before.
They are very useful! :) Thank you very much!..

Leandro


On Sun, Jun 9, 2013 at 10:10 PM, Barry Margolin <barmar@alum.mit.edu> wrote:

> In article <mailman.1310.1370826222.22516.help-gnu-emacs@gnu.org>,
>  Leandro Marcolino <leandromarcolino@gmail.com> wrote:
>
> > Hello, everyone!..
> >
> > This time I am trying to find occurrences of:
> >
> > "<span style='color:white'>&#31169;&#31169;&#31169;&#31169;</span>", but
> > the number of &#31169; can change from 1 to many.
> >
> > And I want to replace each &#31169; of the list to a white space (besides
> > removing the <span> clause). So, if there were x "&#31169;", I need x "
> ".
> > Is it possible to do this using replace-regexp?.. Of course I can't just
> > look for "&#31169;" and replace to " ", because I have occurrences of
> > "&#31169;" that are not inside the group "<span
> > style='color:white'></span>".
> >
> > I tried something like "<span
> style='color:white'>\(\(&#31169;\)+\)</span>
> > -> \,(cond (\1 " ")))", but then I lose the information of how many
> > "&#31169;" were there, and everything changes to a single " "....
> >
> > Thanks for your help!.. :)
> >
> > Regards,
> > Leandro
>
> Regular expressions can't count.
>
> I would do it with a keyboard macro. Search for the span, mark it as a
> region, narrow to region, use replace-string to replace each &#31169
> with space, widen.
>
> --
> Barry Margolin, barmar@alum.mit.edu
> Arlington, MA
> *** PLEASE post questions in newsgroups, not directly to me ***
>