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Re: using lisp in replacement string
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From: |
Nicolas Richard |
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Subject: |
Re: using lisp in replacement string |
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Date: |
Wed, 24 Dec 2014 15:56:43 +0100 |
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User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/25.0.50 (gnu/linux) |
Hello,
Guido Van Hoecke <guivho@gmail.com> writes:
> "You can use Lisp expressions to calculate parts of the replacement
> string. To do this, write `\,' followed by the expression in the
> replacement string.
> [...]
> I got the distinct feeling I'm missing something very basic here...
The \, construct is meant for interactive use.
Try it interactively, then do C-x M-: to see what lisp form it produced.
HTH,
--
Nicolas Richard
Re: using lisp in replacement string,
Nicolas Richard <=
Re: using lisp in replacement string, Andreas Röhler, 2014/12/25