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Re: Noob dumb question (extending emacs)

From: Emanuel Berg
Subject: Re: Noob dumb question (extending emacs)
Date: Wed, 03 Nov 2021 02:06:17 +0100
User-agent: Gnus/5.13 (Gnus v5.13) Emacs/29.0.50 (gnu/linux)

Michael Heerdegen wrote:

>> What do you mean by that, do you mean it doesn't say
>> anything, it is just the relationship between these
>> three things?
>> If so, that's good enough for me, but then what does
>> "password length" mean? If "sex", "love" and "god" are
>> passwords of length 3, 4 and 3 respectively, I understand
>> that, but what password length are we talking about when we
>> are just counting?
> I don't understand the question. The password length is the
> length of the string that is used as a password. The number
> of characters of the string. I never meant
> something different.

What does that formula communicate?

The password length is a function of the number of bits of
entropy and the alphabet size? What password is that?
A password of just that length? ... ???

And say that the alphabet is A = {a, b, c} then |A| = 3, the
entropy bits is decided by /dev/urandom, so that doesn't
change either, how can the formula hold for passwords of
different lengths from that alphabet, e.g. "a" (length 1),
"aa" (2), "abc" (3), and so on?

underground experts united

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