[Help-gnutls] thread safety of gnutls

[Ang Way Chuang]

Hi all,
    I am very sorry for asking too many questions. I ran a multithread test on gnutls_record_{recv,send}. When there are multiple threads using one of these functions 
 simultaneously, the application will segfault. However, if i protect these functions with mutex, it won't segfault. But i thought gnutls is thread safe by design. 
 
 I've called these in my app:
 
 gcry_control (GCRYCTL_SET_THREAD_CBS, &gcry_threads_pthread);
 gnutls_global_init();
 
 Here is thread function:
void * tls_session(void * data) {  int ret;  char buf[501];  int times;  unsigned int len;  gnutls_session_t session = (gnutls_session_t) data;  
 times = 30;  len = times;  memset(buf, 'a' + (rand() % ('z' - 'a')),  len);  buf[len] = 0;    while (!term && !reload && times--) {   //pthread_mutex_lock(&mutex);   ret = gnutls_record_send(session, buf, len + 1);   //pthread_mutex_unlock(&mutex);    if (ret < 1) {    fprintf(stderr, "Failed tls send %s\n", gnutls_strerror(ret));    break;   }      if (ret == 0)    break;      //pthread_mutex_lock(&mutex);   ret = gnutls_record_recv(session, buf, sizeof(buf));   //pthread_mutex_unlock(&mutex);      if (ret < 1) {    fprintf(stderr, "Failed tls recv %s\n", gnutls_strerror(ret));    break;   }      if (ret == 0)    break;     }     return NULL; }
If the pthread_mutex_{un,}lock is commented
 out. Are gnutls functions supposed to be protected using synchronization primitives? Thanks in advance.
 
 Regards,
 Ang Way Chuang
 
 

May you be well and happy

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