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[Help-gsl] overflow exception
From: |
A J |
Subject: |
[Help-gsl] overflow exception |
Date: |
Sun, 18 Jun 2006 00:37:15 -0500 |
Hey All:
While trying to use gsl_sf_exp_e10_e, I get the following error:
gsl: exp.c:127: ERROR: overflow
Default GSL error handler invoked.
Aborted
In my application, I have two numbers a and b and I have to compute a
quantity that's exp(a)/(exp(a)+exp(b)). Now if exp(a) overflows and exp(b)
is in range, I can interpret this as 1. Similarly, if exp(b) overflows and
exp(a) is in range, I can interpret this as 0. Similar interpretations
could be derived for the case in which there's an underflow.
Therefore, it would be nice if I can figure a way in which instead of
throwing an error, the program outputs an alternative integer which could be
0 if there's neither underflow or overflow, 1 if there's an overflow and 2
if there's an underflow (however I am not sure what I can do when both
overflow or both underflow). Does anyone know how to do this?
Thanks,
A
- [Help-gsl] overflow exception,
A J <=