Re: [Help-gsl] General CBLAS question

[bangbang]

BLAS is actually a standard, and it is well documented somewhere else. I think 
you are suppose to read the references listed in the GSL document if you want 
to learn more about it.



在 Sep 10, 2010，3:06 PM，Rodney Sparapani <address@hidden> 写到：

> On 09/ 9/10 03:25 PM, Benjamin Blumer wrote:
>> Hi Rodney,
>> 
>> That's just the way you do it.
>> 
>> Ben
>> 
>> 
>> 
>> On 10-09-09 04:01 PM, Rodney Sparapani wrote:
>>   
>>> I looked for this in the GSL docs, but maybe it is too basic.
>>> I also looked at the source, but I must be missing something.
>>> Anyways, many CBLAS functions calculate something like
>>> y = a A x + b y.  I need (and have tried) the following which
>>> seems to work: y = 1 A y + 0 y.  Is that OK or will you run
>>> into trouble somehow.  Any pointers welcome.  Thanks
>>> 
>>> Rodney
>>>     
> I suppose this is not a FAQ.  But, does anyone else think this is
> sufficiently non-obvious enough to document?  I don't have much
> experience with using BLAS/CBLAS; hence my question.  Would enough
> other people have the same naive question to make a doc change
> beneficial?
> 
> -- 
> Rodney Sparapani       Center for Patient Care and Outcomes Research
> Sr. Biostatistician               http://www.mcw.edu/pcor
> 4 wheels good, 2 wheels better!   Medical College of Wisconsin (MCW)
> WWLD?:  What Would Lombardi Do?   Milwaukee, WI, USA
> 
> 
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