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Re: How to replace %output with #$output?
From: |
Mekeor Melire |
Subject: |
Re: How to replace %output with #$output? |
Date: |
Tue, 22 Mar 2022 07:26:38 +0000 |
2022-03-21 / 21:57 / me@tobias.gr:
> Remove the quote after arguments (replace it with a plain LIST call) and add
> #~ before (modify-phases ...) to define a gexp.
>
> Untested example:
>
> (arguments
> (list #:tests? #f ; no tests
> #:make-flags (list "CC=gcc")
> #:phases
> #~(modify-phases %standard-phases
> (delete 'configure)
> (add-after 'unpack 'patch-makefile
> (lambda _
> (substitute* "Makefile"
> (("/usr/local")
> #$output)))))))
With these changes I get this error:
Wrong type to apply: "CC=gcc"
> So does hard-coding 'gcc' over using (cc-for-target).
Yes, I would also prefer to use cc-for-target. But I wanted to simplify
my code first. Because in order to use cc-for-target, I have to use
backticks. If you have a suggestion for how to use both cc-for-target
and #$output, let me know.
> Very strong opinions on Scheme coding style, that boy.
Please don't assume gender. But yes, you can refer to me with the "he"
pronoun.