Re: variable number of arguments to functions

[Paul D. Smith]

%% Noel Yap <address@hidden> writes:

  ny> Is there a way for me to write a function that has no maximum
  ny> number of arguments?  For example, I'd like to be able to do:

  ny>   $(call exec-commands,echo bar, ls foo)
  ny>   $(call exec-commands,echo another, ls this, ls that)
  ny>   $(call exec-commands,echo one more, ls aoeu, ls ueoa, ls snth)

I don't think so.  A user-defined function can take as many arguments as
you like, up to the limits of memory.  However, I can't think of any way
to write the function itself, because there's no way to specify "all the
arguments to this function".

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