Re: compiler flags

[Paul D. Smith]

%% "Fred J." <address@hidden> writes:

  fj> I think I have a wrong syntax for the flags, I need to
  fj> compile my c++ code for gdb debugging, that is include
  fj> the (-g) flage. is this correct?

  fj> proj1: $(OBJS)
  fj> <TAB> $(CXX) -og $@ $(OBJS)

This question isn't about make, actually: it's about your compiler.  The
flags that your compiler accepts are something you'll have to check the
docs for the compiler to discover.


However, in a traditional UNIX-type C compiler the -o flag takes the
output file as an argument.  So, what you have above:

    -og $@ $(OBJS)

is wrong: it means "link a bunch of files including $@ and $(OBJS), then
write the output to the file 'g'".

You need to write it like this:

    -g -o $@ $(OBJS)

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