Re: @echo name1 = $(name1) does not work

[Paul D. Smith]

%% Morten Gulbrandsen <address@hidden> writes:

  mg> make
  mg> cc -c -o helloworld.o helloworld.c
  mg> cc    -o helloworld helloworld.o

  mg> according to the manual
  mg> http://www.gnu.org/software/make/manual/html_chapter/make_3.html#SEC13
  mg> then you would expect to see this output:

  mg> name1 = Makefile
  mg> name2 = inc.mk

Why would you expect to see that?

Make always runs the first defined target; in this case you include
inc.mk, which defines the target "helloworld" first, before you define
the "all" target.

So, when you run make, it builds helloworld.

If you want it to build "all", then either run "make all" or define that
target first before including inc.mk.

-- 
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