Re: ifeq behaves differently on linux (using GNU Make 3.80) and Solaris (using GNU Make 3.81)

[Oleksandr Gavenko]

On 24.06.2010 14:59, springer83 wrote:
> HI ,
>         I am porting an application from linux to solaris but ifeq behaves
> differently on  linux (using GNU Make 3.80) and Solaris (using GNU Make
> 3.81) ,
>
> Below is the snippet wat i am using on linux :
> " ""
> " ""
> ifeq ($(OS), linux)
> export CPPFLAGS += -DOS_LINUX -D_GNU_SOURCE -D_REENTRANT
> echo "HIIIIIII"
> endif
> " ""
> " ""
> If i build the above snippet on linux it says ::: *** missing separator.
> Stop.
>
>
> ********************************************************************
> Below is the snippet wat i am using on Solaris :
> " ""
> " " ""
> ifeq ($(OS),SunOS)
> export CPPFLAGS += -DOS_SOLARIS -D_GNU_SOURCE -D_REENTRANT
> echo "HIIIIIII"
> endif
> " """
> " """
> If i build the above snippet on Solaris :::: make doesn't crib , but never
> enter's the ifeq condition ...
>
> The  OS variable is getting set to SunOS ,when i echoed..
>
> Can anyone throw some light on this ....thanks in advance
>
> regards
I explore efficient way to debug Makefiles: put $(error $(VAR)) into 
some part of Makefile.

Also exist $(info ...) but it introduced in Make 3.80 if I remember 
correctly.

So before ifeq print $(OS  value) to test if it equal 'SunOS', then put 
$(error ..) into
ifeq to see if error happen (so you enter to 'ifeq' part!).

--
С уважением, Александр Гавенко.