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RE: How does $(error) work?

From: Warlich, Christof
Subject: RE: How does $(error) work?
Date: Thu, 9 Dec 2010 15:12:19 +0100

Chris Cross wrote:
> Trying to understand how $(error) works. The manual says "error is
> generated whenever this function is evaluated."  With the makefile below I
> would expect to see output from line1 of the recipe but only see output
> from $(error).
> #
> .PHONY: target
> target:
>       @echo recipe line 1
>       $(error debug exit recipe line 2)
> $ make -f
> *** debug exit recipe line 2.  Stop.

Make immediately terminates when it sees the $(error) function. And it 
evaluates functions _before_ running any reciepe.

Just replace error with warning: Then, you'll see both the evaluation of the 
$(warning) function (first!), and _then_ the execution of the reciepe.



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