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RE: why does $$(shell bomb with a semicolon during SECONDEXPANSION?
From: |
Paul Smith |
Subject: |
RE: why does $$(shell bomb with a semicolon during SECONDEXPANSION? |
Date: |
Tue, 13 Dec 2011 18:44:29 -0500 |
On Tue, 2011-12-13 at 14:51 -0800, Mark Galeck (CW) wrote:
> Hmm, I did try that, did not work for me, same error (but Philip's solution
> works)
>
> >Another solution that works here is to use backslashes:
>
> foobar: $$(shell echo prereq\;)
Ah right. That's a bug that was fixed since 3.82 was released. Works
now in the current latest sources:
$ cat Makefile
.SECONDEXPANSION:
all: $$(shell echo prereq\;)
@echo hi
$ ~/src/make/make-rel/make
make: *** No rule to make target `prereq', needed by `all'. Stop.
But Philip's solution works as well as you point out.
--
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Paul D. Smith <address@hidden> Find some GNU make tips at:
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