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RE: LU decomposition/backsubstitution
From: |
John W. Eaton |
Subject: |
RE: LU decomposition/backsubstitution |
Date: |
Mon, 6 Dec 1999 14:04:40 -0600 (CST) |
On 6-Dec-1999, Michael Hanke <address@hidden> wrote:
| One could use the LU decomposition [L,U]=lu(A), and
| then x=U\(L\b). This works efficiently if octave sees that L and U are
| triangular (at least after permutation). Does octave see this?
No, not yet.
jwe
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