[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
eval and struct
From: |
Iago Mosqueira |
Subject: |
eval and struct |
Date: |
Fri, 22 Nov 2002 15:19:44 -0000 |
Hi,
I am assigning columns of a matrix (y) to elements in a structure (mat),
reading the names from a cell of strings (names), as in
for el=1:ncols
eval(['mat.' names(el,:) '=y(:,' num2str(el) ');']);
endif
Everything goes fine until the last element, when I get this error
(LnPosterior is the name stored in the last field of the cell):
error: structure has no member 'LnPosterior'
but all previous assigments, 9 if that matters, worked fine. If I issue in
the debug command line mat.LnPosterior=y(:,10), then it works, but not
through eval.
Any ideas what might be happening? Many thanks,
iago
-------------------------------------------------------------
Octave is freely available under the terms of the GNU GPL.
Octave's home on the web: http://www.octave.org
How to fund new projects: http://www.octave.org/funding.html
Subscription information: http://www.octave.org/archive.html
-------------------------------------------------------------
- eval and struct,
Iago Mosqueira <=