[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: Newbie question solving lin sys
From: |
William Lash |
Subject: |
Re: Newbie question solving lin sys |
Date: |
Fri, 27 Dec 2002 17:53:02 -0600 |
Try
help format
format long
x
---------- Original Message ----------------------------------
From: John B. Thoo <address@hidden>
Date: Fri, 27 Dec 2002 15:10:15 -0800
>Bill (or others)---
>
>I'm sorry, but I have at least one more question about this. I get this
>for the list of coefficients when I enter in Octave
>
>octave:92> for i = [1:12]
> > x(i)
> > end
>ans = 22
>ans = 129.32
>ans = -330.01
>ans = 356.74
>ans = -211.74
>ans = 77.512
>ans = -18.446
>ans = 2.9092
>ans = -0.30191
>ans = 0.019818
>ans = -7.4570e-04
>ans = 1.2250e-05
>
>But these numbers lead to erroneous calculations. My question is, does
>Octave keep track of more digits (greater precision) somehow when I use
>x(1), x(2),... instead?
>
>Thanks again.
>
>---John.
>
>
>On Friday, December 27, 2002, at 02:15 PM, William Lash wrote:
>
>> Whenever you type in the numbers for you calculation in s you are
>> losing precision. Instead of typing in:
>>
>>> octave:55> 22 + 129.32*s - 330.01*s**2 + 356.74*s**3 - 211.74*s**4 +
>>> 77.512*s**5 - 18.446*s**6 + 2.9092*s**7 - 0.30191*s**8 +
>>> 0.019818*s**9 -
>>> 0.0007457*s**10 + 0.00001225*s**11
>>
>> Try the following:
>>
>> x(1)+x(2)*s+x(3)*s**2+x(4)*s**3+x(5)*s**4+x(6)*s**5+x(7)*s**6+x(8)*s**7+x(
>> 9)*s**8+x(10)*s**9+x(11)*s**10+x(12)*s**11
>
>
-------------------------------------------------------------
Octave is freely available under the terms of the GNU GPL.
Octave's home on the web: http://www.octave.org
How to fund new projects: http://www.octave.org/funding.html
Subscription information: http://www.octave.org/archive.html
-------------------------------------------------------------