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## Re: legend on contour plot

**From**: |
Henry F. Mollet |

**Subject**: |
Re: legend on contour plot |

**Date**: |
Sat, 09 Feb 2008 16:21:17 -0800 |

**User-agent**: |
Microsoft-Entourage/11.1.0.040913 |

I have the same problem. Using peaks() shows that axis should be axis ([-3,
3, -3, 3]) and that the contours should be between -6 and + 6. It appears
that the axis, when using contour (peaks) are based on the default mesh
value N-by-N = 49.
Function File: [X, Y, Z] = peaks (...)
Generate a function with lots of local maxima and minima. The
function has the form
f(x,y) = 3*(1-x)^2*exp(-x^2 - (y+1)^2) ...
- 10*(x/5 - x^3 - y^5)*exp(-x^2-y^2) ...
- 1/3*exp(-(x+1)^2 - y^2)
Called without a return argument, `peaks' plots the surface of the
above function using `mesh'. If N is a scalar, the `peaks' returns
the values of the above function on a N-by-N mesh over the range
`[-3,3]'. The default value for N is 49.
Henry
on 2/9/08 12:09 AM, Marco Caliari at address@hidden wrote:
>*> There is no way yet to label the contour lines.. The only legend*
>*> possible at the moment is with "colorbar()". See*
>*> *
>*> contour(peaks)*
>*> colorbar*
>* *
>* I see... nothing. White empty room is created on the right, but no color*
>* bar. Moreover, the axes limits are not correct: a level curve is cutted on*
>* the top. GNU Octave 3.0.0 for Windows.*
>* *
>* Marco*
>* _______________________________________________*
>* Help-octave mailing list*
>* address@hidden*
>* https://www.cae.wisc.edu/mailman/listinfo/help-octave*