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Regarding Curve fit
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From: |
Raghavendra K |
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Subject: |
Regarding Curve fit |
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Date: |
Mon, 25 Aug 2008 16:01:45 +0530 |
Hi,
I am trying to use Weibull Curve fit in octave.
Suppose x = [1 2 3]
y=[0.4 0.8 0.9]
I want to find the next value of y(4) for x = 4 using weibull distribution.
How do I go about it?
Thanks for the help.
--
Regards,
Raghavendra K
- Regarding Curve fit,
Raghavendra K <=