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Nonlinear fitting with lg(a+x)
From: |
reposepuppy |
Subject: |
Nonlinear fitting with lg(a+x) |
Date: |
Fri, 13 Mar 2009 01:20:53 -0700 (PDT) |
Hello,
I'm a college student who is attending a physical chemistry class now, and
we're required to process the data obtained from experiments we've done to
reach a plausible conclusion every week.
This time, I've got 2 columns of data, and one of them is the concentration
of a solution [c], the other the surface tension of the solution [r]; the
task is to draw the curve representing the function of F(c,r)=0, and use it
to draw the curve representing the function of F(c, dr/dc)=0 to reach some
conclusionã€‚I found out on the Internet that there is a function between them
stated as :
r=r0[1-a*lg(1+c/b)]
where r0 is the surface tension when there is no solute in the solution, or
in other words, c=0; it could be measured during the experiment. The
constants a and b could be determined by making a nonlinear fitting using
the data I've got.
That's the question: I don't know how to transform this nonlinear function
into a linear one; I could only make it (1-r/r0)=a*lg(b+c)-a*lg(b) and using
the trial-and-error method(*See below) to find out what a and b are. But the
error is too much for me(about 30% away from the theoretical one).
Does anyone know how to solve this fitting problem using solely Octave?
Thanks for help!
* The trial-and-error method I used is here, using Microsoft Excel (I could
use Octave only to deal with some integration problem and linear
fitting...):
First, input the data into Excel and draw a XY scattered diagram, where
X=(1-r/r0) and Y=lg(b+c). A linear distribution of dots would appear if the
value of b was right.
Second, calculate the R^2(the square of correlation coefficient) . It would
be a value very close to 1 if the value of b was right.
Third, change the b value until I can't make the R^2 higher. First try from
0 to 10, and find out the optimal value, and minimize the scale by 10 fold
and try again... I tried from 0 to 2, and found out the R^2 will be the
biggest when b was 0.6; and I tried from 0.50 to 0.70 and I found out it's
0.59~0.62(the R^2 will not change any more during this range).
--
View this message in context:
http://www.nabble.com/Nonlinear-fitting-with-lg%28a%2Bx%29-tp22492005p22492005.html
Sent from the Octave - General mailing list archive at Nabble.com.
- Nonlinear fitting with lg(a+x),
reposepuppy <=
- Re: Nonlinear fitting with lg(a+x), Jaroslav Hajek, 2009/03/13
- Re: Nonlinear fitting with lg(a+x), reposepuppy, 2009/03/16
- Re: Nonlinear fitting with lg(a+x), Michael Creel, 2009/03/16
- bfgsmin, Bertrand Roessli, 2009/03/16
- Re: bfgsmin, Michael Creel, 2009/03/16
- Re: bfgsmin, Bertrand Roessli, 2009/03/16
- Re: bfgsmin, Michael Creel, 2009/03/16
- Re: bfgsmin, Bertrand Roessli, 2009/03/16
- Re: bfgsmin, Michael Creel, 2009/03/16
- Re: bfgsmin, Bertrand Roessli, 2009/03/17