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## RE: binomial_rnd

**From**: |
Richardson, Anthony |

**Subject**: |
RE: binomial_rnd |

**Date**: |
Thu, 25 Feb 2010 07:08:16 -0600 |

It works fine for me:
$ z = binorand(40, .5, 1000, 1);
$ mean(z)
ans = 19.944
Tony
>* Dupuis [mailto:Pascal dot Dupuis at worldonline dot be] wrote:*
>* Subject: binomial_rnd*
>* *
>* *
>* Hello,*
>* *
>* while looking at*
>* http://en.wikipedia.org/wiki/Binomial_distribution#Mean_and_variance*
>* it states that, for a Binomial distribution with parameters N and P,*
>* mean = N*P*
>* variance = N*P*(1-P)*
>* *
>* but*
>* z=binornd(40, .5, 1000, 1)*
>* generates a discrete variable whose mean is far different from the*
>* expected*
>* value of 20. Any idea ?*
>* *
>* Regards*
>* *
>* Pascal*

**binomial_rnd**, *Dupuis*, `2010/02/25`
**RE: binomial_rnd**,
*Richardson, Anthony* **<=**