assign struct array to cell array

[Eric Chassande-Mottin]

hi, I'd like to assign a struct array to a cell array.
I'm wondering whether I could do that without a loop
like in this example :

clear; a=cell(3,1); b.foo=1; b(2).foo=2; b(3).foo=3; for n=1:3, a{n}=b(n);
endfor; a
a =

{
  [1,1] =
  {
    foo =  1
  }

  [2,1] =
  {
    foo =  2
  }

  [3,1] =
  {
    foo =  3
  }
}

all my attempts end up creating a cell array with three copies of b, e.g.:

clear; a=cell(3,1); b.foo=1; b(2).foo=2; b(3).foo=3; [a{:}]=deal(b(:))

I guess the reason is that b(:) isn't a cs list.

eric
-- 
View this message in context: 
http://octave.1599824.n4.nabble.com/assign-struct-array-to-cell-array-tp3029362p3029362.html
Sent from the Octave - General mailing list archive at Nabble.com.