|Subject:||Re: Curve fit|
|Date:||Mon, 22 Nov 2010 11:47:21 -0800|
On Nov 22, 2010, at 6:34 AM, Martin Maxino wrote:
While the answers you got from James are correct, you could use the non-linear curve fit instead:
You don't really need to use .* in this case since the multiplications are between a vector and a scaler, not between two vectors. (In my emails to Cunninghands, I did put dots a couple of places where they were not really necessary. Sorry about that.)
Whether you make the pre-exponential factor an unknown parameter (as in the example above) or a known constant depends on what you know for a fact. If you know the actual initial condition (as opposed to measuring it), just fit for one unknown parameter. In the example above, in the first guess for the parameters, [10;.1], you could use a measured value for c(1) in place of the 10.
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