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Re: Yet Another Vectorization Quiz
From: |
c. |
Subject: |
Re: Yet Another Vectorization Quiz |
Date: |
Wed, 15 Dec 2010 00:07:05 +0100 |
Ben,
On 14 Dec 2010, at 23:39, bpabbott wrote:
> [~, n] = sort (a==0);
> a = a (ones (size (a, 1), 1) * (0:size (a, 2) - 1) * 4 + n)
Thanks! This works great (thoug I'm still trying to fully understand why ;) )
except for the '[~, n]' syntax, maybe this requires the developement version?
I need the code to be compatible with 3.2.4 so I', using
[ignore, n] = sort (a==0);
I guess '4' stands for size (a, 1), right?
Thanks again!
c.