----- Original Message -----
> From: Ben Abbott <
address@hidden>
> To: Sergei Steshenko <
address@hidden>
> Cc: "
address@hidden" <
address@hidden>
> Sent: Thursday, February 2, 2012 3:47 PM
> Subject: Re: 'for' loop on elements of cell array (octave-3.4.2) - is it the way it is supposed to be ?
>
> On Feb 2, 2012, at 6:39 AM, Sergei Steshenko wrote:
>
>> Hello,
>>
>> I have tried the following piece of code:
>>
>> "
>> octave:1> foolist = {1, 2, 5}
>> foolist =
>> {
>> [1,1] = 1
>> [1,2] = 2
>> [1,3] = 5
>> }
>> octave:2> for foo = foolist foo endfor
>> foo =
>> {
>> [1,1] = 1
>> }
>> foo =
>> {
>> [1,1] = 2
>> }
>> foo =
>> {
>> [1,1] = 5
>> }
>
> <snip>
>
>> In other words, the output from the 'for' loop doesn't look
> like I expect, and if my expectations (I expected '1, 2, 5' sequence)
> are wrong, which part of GNU Octave documentations explains how the output
> should look ?
>
> I'm confused. The output is 1, 2, 5.
>
> The for loop below will run 3 times (once for each column)
>
> for a = [1 2 3; 4 5 6; 7 8 9]
> disp (a)
> disp ('---')
> end
> 1
> 4
> 7
> ---
> 2
> 5
> 8
> ---
> 3
> 6
> 9
> ---
>
> This one will only perform one loop
>
> for a = [1 2 3; 4 5 6; 7 8 9](:)
> disp (a)
> disp ('---')
> end
> 1
> 4
> 7
> 2
> 5
> 8
> 3
> 6
> 9
> ---
>
> And this one will perform 9 loops
>
> for a = [1 2 3; 4 5 6; 7 8 9](:)'
> disp (a)
> disp ('---')
> end
> 1
> ---
> 4
> ---
> 7
> ---
> 2
> ---
> 5
> ---
> 8
> ---
> 3
> ---
> 6
> ---
> 9
> ---
>
> Does that clarify the behavior ?
>
> Ben