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Re: Control System Question

From: Thomas D. Dean
Subject: Re: Control System Question
Date: Wed, 08 Feb 2012 17:53:38 -0800
User-agent: Mozilla/5.0 (X11; FreeBSD amd64; rv:9.0) Gecko/20120126 Thunderbird/9.0

On 02/08/12 17:34, Doug Stewart wrote:

On Wed, Feb 8, 2012 at 8:24 PM, Thomas D. Dean <address@hidden
<mailto:address@hidden>> wrote:

    On 02/08/12 17:00, Doug Stewart wrote:

        y(n) = y(n-1) + (1/F1 + 1/F2)*x(n) + (1/F1 - 1/F2)*x(n-1)

The time equation involves y(n), y(n-1), x(n), and, x(n-1)

In z space this is
y=yZ^-1 + (a) xZ^-1  +bxZ-2

I have been reading

Figure 3-2-8 shows my system.

Guess I need to read some more.

Tom Dean

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