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Re: Control System Question

From: Doug Stewart
Subject: Re: Control System Question
Date: Wed, 8 Feb 2012 20:57:40 -0500

On Wed, Feb 8, 2012 at 8:53 PM, Thomas D. Dean <address@hidden> wrote:
On 02/08/12 17:34, Doug Stewart wrote:

On Wed, Feb 8, 2012 at 8:24 PM, Thomas D. Dean <address@hidden
<mailto:address@hidden>> wrote:

   On 02/08/12 17:00, Doug Stewart wrote:

       y(n) = y(n-1) + (1/F1 + 1/F2)*x(n) + (1/F1 - 1/F2)*x(n-1)

The time equation involves y(n), y(n-1), x(n), and, x(n-1)

In z space this is
y=yZ^-1 + (a) xZ^-1  +bxZ-2

I have been reading

Figure 3-2-8 shows my system.

Guess I need to read some more.


Tom Dean
Help-octave mailing list

and just below is


The transfer function of a 3th order IIR filter, designed using Chebyshev function is:

Formula 3-2-13

This is a 3rd order yours was a second order.


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