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Re: fzero tolerance issue ... and a related bug


From: marco atzeri
Subject: Re: fzero tolerance issue ... and a related bug
Date: Thu, 18 Oct 2012 20:31:14 +0200
User-agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:16.0) Gecko/20121010 Thunderbird/16.0.1

On 10/18/2012 7:46 PM, Joza wrote:
So related to all that above, how does one find the root of a function that
is always positive, or zero, but never negative? For instance, an absolute
value:  f(x) = abs(x - 2)

look for the minimum
http://www.gnu.org/software/octave/doc/interpreter/Minimizers.html#Minimizers


This has root 2, but I can't give it an initial bracket [x1,x2] since
f(x2)*f(x2) >= 0.
Indeed, how could fzero even find an initial bracket?

So how can one solve such a simple equation with fzero?






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