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## Re: how to vectorize in the octave

 From: Herier chen Subject: Re: how to vectorize in the octave Date: Mon, 12 Nov 2012 14:52:55 -0500

yep, thanks for  your help. after considering your advice and I have just gotten rid of the for loop and the i and take replace of the " * " with the " .* " .

grad = (1.0/m) .* X' * (h-y);

it works now!!
Thank for you help. and hoping you have a nice day

On Mon, Nov 12, 2012 at 2:45 PM, Ed Meyer wrote:

On Mon, Nov 12, 2012 at 11:33 AM, Herier chen wrote:
yes, it is from professor Andrew Ng  the on-line coursesa class about machine learning.

I am doing the ex3 now. I started the class a little late.

On Mon, Nov 12, 2012 at 2:27 PM, Ed Meyer wrote:

On Mon, Nov 12, 2012 at 9:39 AM, Herier chen wrote:

Hi, all, I am new for the octave, and I want to know how to vectorize the following code, I have tried lots of time ,but failed. would anybody do me a favor to help. thanks.

h = sigmoid(X*theta);

for i=1:m1,

end

and another question about the octave.

what is the difference between "/" and "./" . and how to find these operators definition in the octave help document. I have not find these all kinds of operators in octave.

thanks a lot/

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which exercise is this? (I assume it is from Dr. Ng's ML class)

--
Ed Meyer

You can almost always figure out the correct form by considering the dimensions
of the matrices;  in this case X is m by n, theta is (n,1), h = sigmoid(X*theta) is (m,1)
so to vectorize the gradient calculation you want something like

grad = X' * (h - y)/m

(n,1) = (n,m) * (m,1)

--
Ed Meyer

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