help-octave
[Top][All Lists]

## Fwd: Multivariate student t: normalization in mvtrnd

 From: Iñigo Urteaga Subject: Fwd: Multivariate student t: normalization in mvtrnd Date: Mon, 26 Nov 2012 17:22:26 -0500

```Dear all,

I am using the mvtrnd function provided in the statistics package for
octave and I have encountered some inconsistent results that I do not
comprehend.

>From theory, we know that if Z is a standard Student's t random vector
and we define X as a linear combination (i.e. X=Sigma * Z), the
resulting variable X is a multivariate Student's t distribution with
covariance matrix Var(X)=nu/(nu-2)*V, where V=Sigma * Sigma'.

In fact, when we define a V and sample from the following expression,
where Sigma=chol(V), n is the dimensionality, nu the degrees of
freedom and M the number of samples:

samples=Sigma' * mvtrnd( eye(n), nu, M)'; (1)

the covariance computed from those samples (i.e. cov(samples) )
matches the expected variance nu/(nu-2)*V.

However, if we directly apply:

samples=mvtrnd(V, nu); (2)

then, the covariance computed does not match  nu/(nu-2)*V, but the
alternative expression using the correlation matrix R: nu/(nu-2)*R.
Here, R is the correlation matrix as computed by
R=V./(sqrt(diag(V)*diag(V))). The mvtrnd code indicates that the
provided V is normalized if diagonal elements are non-unit, but I
don't understand why this is required. In fact, sampling from the
multivariate normal (mvnrnd called within the function) actually
performs Cholesky decomposition of the provided V to accommodate non
unitary covariance matrices.

As I understand it, both approaches (1) and (2) should provide the
same result (and that is the case if no normalization is performed).
Since this is not the case, I was wondering what is the underlying
reason for that normalization step. Am I missing something here or is
this normalization step in mvtrnd unnecessary?

I would truly appreciate some help/hints here.

Thank you very much in advance,

Iñigo Urteaga

```