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Re: Short Cut Way to Assign the Variables x1, x2....x40 names
From: |
Fausto Arinos de A. Barbuto |
Subject: |
Re: Short Cut Way to Assign the Variables x1, x2....x40 names |
Date: |
Sun, 14 Sep 2014 19:25:28 -0300 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.1.1 |
On 13-09-2014 15:43, Ed Song wrote:
Hello,
I have a 40 period model and want to assign the variable x1, x2...x40 names
without having to
write the same subroutine 40 times. I remember in Fortran and Pascal we use to
assign the
variable x an index i, hence xi. Then use a Do Loop to calculate x1 through x40
without having
to write out the routine 40 times. I'm trying to make heads or tails out of the
manual, but am
having a difficult time. Is there a w ay I can make the calculation 40 times
doing the routine
once instead of 40 times?
For example, suppose x1 = y1 + a, and x2 = y2 + a...x40=y40+a
In Fortran we would write a program something like this:
Do i=1,40
xi=yi+a
In Fortran, the two statements above would sum the scalar "a" to the *scalar*
"yi" 40 times,
assigning the result to the *scalar* xi the same 40 times. And whichever the values of
"a"
or "yi", "xi" would always have the same value in the end, be "i" either 1, 2,
..., 40,
whatever. Doesn't make a whole lot of sense. What you perhaps meant is:
Do i = 1, 40
x(i) = y(i) + a
End Do
Be aware though that, for example, x(1) = y(1) + a is not the same as x1 = y1 +
a.
x(1) and y(1) are members of an array, whereas x1 and y1 are scalars.
Therefore, what
you suggested can't be done in Fortran.
In the following program I didn't have to write out x2=y2+a, x3=y3+a...etc.
Is there a similar procedure in Gnu Octave? How would I write an equivalent
program to the above
in Gnu Octave?
Ed
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