
From:  Nicholas Jankowski 
Subject:  Re: Octave: sympy error? 
Date:  Fri, 18 Nov 2016 10:10:47 0500 
On Fri, Nov 18, 2016 at 6:28 AM, Constantine Frangos <address@hidden> wrote:
There seems to be an error in the sympy 1.0 limit() function.
The lim(1/x) as x>0 does not exist while the limit()
function indicates this as +infinity.
It seems that a custom octave function could compute the
left and right limits in order to get a better understanding.
Regards,
Constantine.
octave:20> limit(1/x,x,0)
ans = (sym) oo
octave:21>
octave:21> limit(1/x,x,0,'right')
ans = (sym) oo
octave:22> limit(1/x,x,0,'left')
ans = (sym) oo
Yes, and this does appear to be a matlab incompatibility:Matlab 2016b:
>> limit (1/x,x,0)
ans =
NaN
>> limit (1/x,x,0,'right')
ans =
Inf
>> limit (1/x,x,0,'left')
ans =
Inf
[Prev in Thread]  Current Thread  [Next in Thread] 