
From:  shankara naryana 
Subject:  Re: having difficulty using a for loop to solve an equation 
Date:  Mon, 19 Jun 2017 18:26:48 0600 
here is my task:
<http://octave.1599824.n4.nabble.com/file/n4683785/ >Screenshot_20170619_1754 18.png
Create two arrays x and y, whose entries are defined as
x = i,
y = j
i = 1, 2, 3, 4, 5.
y=5 − 2j,
j = −2, −1, 0, 1, 2.
Then, compute the cubed sum of these two vectors in two different ways.
First, use a for loop
to construct the vector z as
z = (x + y )^ 3 ,
i = 1, 2, 3, 4, 5.
my code:
%Vectorization
clc;
clear;
%x=i; %array created per spec
%i=[1 2 3 4 5]; %array created per spec
y=52j; %array created per spec
j=[2 1 0 1 2]; %array created per spec
z=(y).^3; %formula to test for loop
for m=j
t=z
end
the result:
t = 65  142i
t = 65  142i
t = 65  142i
t = 65  142i
t = 65  142i
I know the answer should be t= (the cube for the elements in j)
I'm new to octave but I've always needed adult supervision with loops. What
am I missing?

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