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Re: [Help-smalltalk] [PATCH] kernel: Check the Semaphore before queuing
Re: [Help-smalltalk] [PATCH] kernel: Check the Semaphore before queuing the interrupt
Tue, 21 Jan 2014 18:11:47 +0100
Mozilla/5.0 (X11; Linux x86_64; rv:24.0) Gecko/20100101 Thunderbird/24.2.0
Il 20/01/2014 20:30, Holger Hans Peter Freyther ha scritto:
On Mon, Jan 20, 2014 at 05:30:52PM +0100, Paolo Bonzini wrote:
The patch looks good.
Alternatively, what about this? It is a bit clearer to me, but the
logic is pretty much the same.
(self timedWaitOn: sem) ifTrue: [
- proc signalInterrupt: (Kernel.TimeoutNotification on: self).
+ timeout = 0 ifTrue: [
+ proc signalInterrupt: (Kernel.TimeoutNotification on:
If we ever get the execution of multiple native processes the timeout
code and the aBlock ensure: could run at the same time. How would we
make that mutual exclusive? add a lock/token then?
We probably would need syntax for atomic compare and exchange of OOPs.