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## Re: [igraph] Graph isomorphism

 From: Gábor Csárdi Subject: Re: [igraph] Graph isomorphism Date: Tue, 7 Jul 2015 11:15:05 +0200

```g[i] is a list of length one. Use double brackets to extract the list
element: g[[i]].

Gabor

On Tue, Jul 7, 2015 at 11:10 AM, priyanka nimavat
> Hi all,
> i am having problem in finding graph isomorphism together of 5 graph
> objects.As an example my r script is as follow.
>
> g1 <- graph.ring(10 , directed = FALSE)
> g2 <- graph.ring(5 , directed = FALSE)
> g3 <- graph.ring(7 , directed = FALSE)
> g4 <- graph.ring(6 , directed = FALSE)
> g5 <- graph.ring(8 , directed = FALSE)
>
> g <- list(g1,g2,g3,g4,g5)
> g
>
>
> iso = function(g , i ,j)
> {
>   r <- graph.isomorphic(g[i],g[j])
>   return(r)
> }
>
> for(i in 1:5)
> {
>   for(j in 1:5)
>   {
>     r= iso(g , i , j)
>     print(r)
>   }
> }
>
> It is giving an error that g is not a graph object. Because in function
> graph.isomorphic it is only accepting graph objects. Is there any way to
> find isomorphism of multiple graph objects together using for loop.
> Thanks.
>
>
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